Question

Factorise : x cube - 3x^ -9x-5
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Answer 1

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Answer 2

Answer:

The factor of the equation is x^3-3x^2-x+3=(x-3)(x-1)(x+1)x

3

−3x

2

−x+3=(x−3)(x−1)(x+1)

Step-by-step explanation:

Given : Equation x^3-3x^2-x+3x

3

−3x

2

−x+3

To find : Using factor theorem factorise equation?

Solution :

Factor theorem is the remainder theorem in which taking common factor from the equation and then divide from the quotient or factories it again.

We try to factor the common from the equation,

x^3-3x^2-x+3x

3

−3x

2

−x+3

=x^2(x-3)-1(x-3)=x

2

(x−3)−1(x−3)

The common factor is (x-3),

=(x-3)(x^2-1)=(x−3)(x

2

−1)

Now, again we factor x^2-1=(x-1)(x+1)x

2

−1=(x−1)(x+1)

Substitute,=(x-3)(x-1)(x+1)=(x−3)(x−1)(x+1)

Therefore, The factor of the equation is x^3-3x^2-x+3=(x-3)(x-1)(x+1)x

3

−3x

2

−x+3=(x−3)(x−1)(x+1)

Easy pisy lemeon creezy

I hope u understand it