factorise: x (cube)-3x (square)-9x-5........ plz solve it....
Answers
Answered by
43
x^3-3x^2-9x-5
=x ^3+x^2 -4x^2-4x-5x-5
= x^2 (x+1)-4x (x+1)-5 (x+1)
=(x+1)(x^2-4x-5)
=x ^3+x^2 -4x^2-4x-5x-5
= x^2 (x+1)-4x (x+1)-5 (x+1)
=(x+1)(x^2-4x-5)
Namo11:
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Answered by
62
x³-3x²-9x-5
=x³+x² -4x²-4x-5x-5
= x² (x+1)-4x (x+1)-5 (x+1)
=(x+1)(x²-4x-5)
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