Factorise x cube-64
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x³-64
(x)³-(4)³
a³-b³= (a-b)(a²+ab+b²)
=(x-4)[(x)²+x×4+(4)²]
=(x-4)(x²+4x+16)
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Answered by
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Answer:
The answer is: x3+64=(x+4)(x2−4x+16).
Step-by-step explanation:
It's easy if we remember the formula of sum of cubes, that says:
x3+y3=(x+y)(x2−xy+y2).
In this case 64=43.
It's also to remember the formula of difference of cubes, that says:
x3−y3=(x−y)(x2+xy+y2).
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