Question

Factorise=x cube+64

Answer 1

hey dear

here is your answer

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to factorise

x^3 + 64

(x)^3 + ( 4 ) ^3

it is in ( a^3 + b^3 ) = ( a ^2 -ab + b^2)

so,

(x + 4) ( x^2 - 4x- 4^2.)

( x^2 - 4x+ 16)

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hope it helps

thank you

Answer 2

$\textbf{Answer :}$

Now,

${x}^{3} + 64 \\ \\ = {x}^{3} + {4}^{3} \\ \\ = (x + 4)( {x}^{2} - 4x + {4}^{2} ) \\ \\ = (x + 4)( {x}^{2} - 4x + 16)$

which is the required factorization.

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