factorise x cube minus 2 x square minus x + 2
Answers
Answered by
13
x^3 - 2x^2 - x + 2
= x^2 (x-2) - 1(x - 2)
= ( x - 2) [ (x)^2 - (1)^2]
= (x-2)(x-1)(x+1)
= x^2 (x-2) - 1(x - 2)
= ( x - 2) [ (x)^2 - (1)^2]
= (x-2)(x-1)(x+1)
Answered by
7
x^3-2x^2-x+2
(x^3-2x^2)+(-x+2)
x^2(x-2)-1(x-2)
(x-2)(x^2-1)
(x-2)[(x^2)-(1^2)]
(x-2)[(x-1)(x+1)] { since a^2-b^2=(a-b)(a+b) }
(x-2)(x-1)(x+1)
hope this answer helps you
please mark as brainliest!!
(x^3-2x^2)+(-x+2)
x^2(x-2)-1(x-2)
(x-2)(x^2-1)
(x-2)[(x^2)-(1^2)]
(x-2)[(x-1)(x+1)] { since a^2-b^2=(a-b)(a+b) }
(x-2)(x-1)(x+1)
hope this answer helps you
please mark as brainliest!!
Similar questions