Question

factorise x cube minus 23 x square + 142 x minus 120 pls help,it's urgent

Answer 1

${x}^{3} - {23x}^{2} + 142x - 120 \\ spilt \: {23x}^{2} \: as \: sum \: or \: difference \: of \: two \: terms \: same \: for \: 142x \\ \\ { x}^{3} - {x}^{2} - {22x}^{2} + 22x + 120x - 120 \\ {x}^{2} (x - 1) - 22x(x - 1) + 120( x - 1) \\ (x - 1)( {x}^{2} - 22x + 120) \\ (x - 1)( {x}^{2} - 10x - 12x + 120) \\ (x - 1)(x(x - 10) - 12(x - 10) \\ (x - 1)(x - 10)(x - 12)$
hope this helps you