Question

factorise:x cube minus 8 y cube + 27 Z Cube + 18 x y z

Answer 1

Hey mate here is your answer.....

This answer is verified ✅✅

${x}^{3} - {8y}^{3 } + 27 {z}^{3} +18xyz$
Here is your solution.....

$= {x}^{3} + {( - 2y})^{3} + {(3z})^{3} - 3 \times x \times ( -2y) \times (3z)$
$= (x + y + z)( {x}^{2} + {y}^{2} + {z}^{2} - xy - yz - zx)$
$= ( x + ( - 2y) + (3z))( {x}^{2} + ( - {2y})^{2} + ({3z})^{2} - x \times( - 2y) - ( - 2y) \times (3z) - (3z) \times( x)$
$= (x - 2y + 3z)( { x }^{2} + 4 {y}^{2} + 9 {z}^{2} + 2xy + 6yz - 3zx)$
hope it will help you....

Answer 2

Answer:

mark it as brainliest please