Question

factorise x cube + y cube + 64 - 12 x y

Answer 1

x^3 +y^3+64-12xy
x^3 +y^3+4^3-3×x×y×4
(x+y+4)^3

Answer 2

Here's your answer !!

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$= > {x}^{3} + {y}^{3} + 64 - 12xy \\ = > {x}^{3} + {y}^{3} + {4}^{3} - 3(x)(y)(4) \\ = > {(x + y + 4)}^{3}$ \\=>{(x+y+4)}{(x+y+4)}{(x+y+4)}
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Hope it helps you!! :)