Math, asked by fremilreji, 7 months ago

Factorise X power2-y power2/100

Answers

Answered by NishchhalJha
0

Answer:

(x+y¹/²⁵)(x-y¹/²⁵)

Step-by-step explanation:

x²-y²/¹⁰⁰

x²-y¹/⁵⁰

(x)²-(y¹/²⁵)²

(x+y¹/²⁵)(x-y¹/²⁵)

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Answered by Anonymous
15

Given:

 \\ {\sf\purple{ Factories: \: \left( x^2 - \dfrac{y^2}{100} \right) }}. \\

Solution:

 \\ {\sf\blue{ \left( x^2 - \dfrac{y^2}{100} \right) = x^2 - \left( \dfrac{y}{100} \right)^2  }} \\ \\ \implies{\sf{ \left( x - \dfrac{y}{10} \right) \left( x + \dfrac{y}{10} \right) \: \: \: \: \: \sf\blue \left[ \because (a^2 - b^2 ) = (a-b) (a+b) \right] }} \\ \\  {\sf{Hence: }}  \\ {\sf { \left( x^2 - \dfrac{y^2}{100} \right) = \left( x - \dfrac{y}{10} \right) \left( x + \dfrac{y}{10} \right) . }} \\

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