Factorise x power4 +x power 2 +1
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56
Given Equation is x^4 + x^2 + 1
= > x^4 + 2x^2 - x^2 + 1
= > (x^4 + 2x^2 + 1) - x^2
= > (x^2 + 1)^2 - x^2
We know that (a^2 - b^2) = (a + b)(a - b)
= > (x^2 + 1 + x)(x^2 + 1 - x)
Therefore, factorization of x^4 + x^2 + 1 = (x^2 + 1 + x)(x^2 + 1 - x).
Hope this helps!
= > x^4 + 2x^2 - x^2 + 1
= > (x^4 + 2x^2 + 1) - x^2
= > (x^2 + 1)^2 - x^2
We know that (a^2 - b^2) = (a + b)(a - b)
= > (x^2 + 1 + x)(x^2 + 1 - x)
Therefore, factorization of x^4 + x^2 + 1 = (x^2 + 1 + x)(x^2 + 1 - x).
Hope this helps!
siddhartharao77:
:-)
Answered by
22
X^4+x^2+1
x^2+x^2+x^2+1
x^2 (x^2+1) 1 (x^2+1)
(X^2+1)(x^2+1)
x^2+x^2+x^2+1
x^2 (x^2+1) 1 (x^2+1)
(X^2+1)(x^2+1)
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