factorise X square + 2 ax minus b square minus 2 a b
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Answered by
93
(x^2-b^2)+(2ax-2ab)
(x+b)(x-b)+2a(x-b)
(x-b)(x+b+2a) ans
(x+b)(x-b)+2a(x-b)
(x-b)(x+b+2a) ans
Answered by
124
Here's the answer
Given,
to factorise
x² + 2ax - b² - 2ab
by regrouping, we have,
x² - b² + 2ax - 2ab
in x² - b² , we will use the 3rd identity ie, a² - b² = (a - b)(a + b ) and in +2ax and -2ab , we will use the method of taking out common factor
so,
(x - b)(x + b)2a( x - b)
it can be seen that (x - b) is a common factor,
Therefore,
is the answer
Given,
to factorise
x² + 2ax - b² - 2ab
by regrouping, we have,
x² - b² + 2ax - 2ab
in x² - b² , we will use the 3rd identity ie, a² - b² = (a - b)(a + b ) and in +2ax and -2ab , we will use the method of taking out common factor
so,
(x - b)(x + b)2a( x - b)
it can be seen that (x - b) is a common factor,
Therefore,
is the answer
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