Question

factorise
X square + 3 under root 3 X + 6

Answer 1

${x}^{2} + 3 \sqrt{3} x + 6 \\ \\ = {x}^{2} + 2 \sqrt{3} x + \sqrt{3} x + 6 \\ \\ = x(x + 2 \sqrt{3} ) + \sqrt{3} (x + 2 \sqrt{3} ) \\ \\ = (x + 2 \sqrt{3} )(x + \sqrt{3} )$

Answer 2

${x}^{2} + 3 \sqrt{3} x + 6 \\ {x}^{2} + 2 \sqrt{3}x + \sqrt{3}x + 6 \\ x(x + 2 \sqrt{3} ) + \sqrt{3} (x + 2 \sqrt{3} ) \\ (x + 2\sqrt{3)} \times (x + \sqrt{3} )$
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