Question

factorise x square +7root6x+60

Answer 1

$x ^{2} + 7 \sqrt{6} x + 60 =$

$x ^{2} + 5 \sqrt{6} x + 2 \sqrt{6} x + 60$

$x(x + 5 \sqrt{6} ) + 2 \sqrt{6} (x + 5 \sqrt{6} )$

$(x + 5 \sqrt{6} )(x + 2 \sqrt{6} )$

so the zeroes are

$- 2 \sqrt{6}$

and

$- 5 \sqrt{6}$

Answer 2

Answer:

+76x+60=

x ^{2} + 5 \sqrt{6} x + 2 \sqrt{6} x + 60x2+56x+26x+60

x(x + 5 \sqrt{6} ) + 2 \sqrt{6} (x + 5 \sqrt{6} )x(x+56)+26(x+56)

(x + 5 \sqrt{6} )(x + 2 \sqrt{6} )(x+56)(x+26)

so the zeroes are

- 2 \sqrt{6}−26

and

- 5 \sqrt{6}−56