Question

Factorise x
$x {}^{3} + 2x {}^{2} - 5x - 6$
+ 2x2 - 5x - 6.​

Answer 1

Answer:

the correct answer is (x-2)(x+3)(x+1)

Step-by-step explanation:

$x^{3} +2x^{2} -5*x-6$

let x=2

$2^{3} +2*2^{2} -5*2-6$ = f(2)

8+2*4-10-6 = f(2)

8+8-16 = f(2)

16-16 =f(2)

0= f(2)

therefore  x-2 is a factor

now divide ( $x^{3} +2x^{2} -5*x-6$) by (x-2)

then by dividing we get $x^{2} +4*x+3$

on complete factorisation we get (x-2)(x+3)(x+1)