Question

factorise x to the power 8- 216

Answer 1

I hope it helps ☺️☺️☺️☺️

Answer 2

Answer:

$(x^2)^3-6^3=(x^2-6)(x^4+36+6x^2)$

Step-by-step explanation:

Given : Expression - $x^8-216$

To find : Factorize the given expression

Solution :

Step 1- Write the expression

$x^8-216$

Step 2- Find their roots or cube roots

$=(x^2)^3-(6)^3$

Step 3- Apply the cube root property $a^3-b^3=(a-b)(a^2+b^2+ab)$

where $a=x^2$ and  $b=x^2$

$(x^2)^3-6^3=(x^2-6)((x^2)^2+6^2+(x^2)(6))$

$(x^2)^3-6^3=(x^2-6)(x^4+36+6x^2)$