factorise x to the power cube minus x
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x^3 - x
x(x^2 - 1)
Now factor (x^2 - 1)
x(x - 1)(x + 1)
x(x^2 - 1)
Now factor (x^2 - 1)
x(x - 1)(x + 1)
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According to given question,
x^3-x=0
Taking x common
=>x(x^2-1)=0
=>now x=0 or (x^2-1)=0
=>x^2=1
=>x=_+underoot1
=>x=1 or x=-1
Hence value of x is 1 or - 1
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