Question

factorise x (x+1)(x+2)(x+3)+1​

Answer 1

Answer:

x + 1)(x + 2)(x + 3)(x + 4) - 15

= [(x + 1)(x + 4)] [(x + 2)(x + 3)] - 15

= [x² + 5x + 4] [x² + 5x + 6] - 15

= [(x² + 5x + 5) - 1] [(x² + 5x + 5) + 1] - 15

= [(x² + 5x + 5)² - 1²] - 15

= (x² + 5x + 5)² - 16

= (x² + 5x + 5)² - 4²

= [(x² + 5x + 5) - 4] [(x² + 5x + 5)+ 4]

= (x² + 5x + 1)(x² + 5x + 9)

Step-by-step explanation: