factorise x(x cube- y cube) + 3xy(x-y)
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x(x^3 - y^3) + 3xy(x- y)
(x - y){x(x^2 + xy + y^2) + 3xy}
(x - y)x{(x^2 + xy + y^2) + 3 y}
x.(x - y)(x^2 + y^2 + xy + 3y)
factor is x and x- y
(x - y){x(x^2 + xy + y^2) + 3xy}
(x - y)x{(x^2 + xy + y^2) + 3 y}
x.(x - y)(x^2 + y^2 + xy + 3y)
factor is x and x- y
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Answer:
step by step explanation :
we know that : a^3 - b^3 = (a-b) ( a^2 + b^2 + xy)
= x(x^3 - y^3) + 3xy(x-y)
= x(x-y) (x^2+y^2+xy) + 3xy(x-y)
take common x(x-y) from 3xy(x-y)
= x(x-y) (x^2 + y^2 + xy +3y)
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