Factorise-x(x+z)-y(y+z)
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Answered by
11
x(x+z)−y(y+z)
= x²+zx−y²−yz
= x²−y²+zx−yz
= (x²−y²)+z(x−y)
=(x−y)(x+y)+z(x−y)
=(x−y)[x+y+z]
Hope it helps:)
= x²+zx−y²−yz
= x²−y²+zx−yz
= (x²−y²)+z(x−y)
=(x−y)(x+y)+z(x−y)
=(x−y)[x+y+z]
Hope it helps:)
Answered by
2
x(x+z)-y(y+z)
x²+xz-y²-yz => x²-y²+xz-yz => (x-y)(x+y)+z(x-y)
(x-y)(x+y+z) is the answer
hope this helps
x²+xz-y²-yz => x²-y²+xz-yz => (x-y)(x+y)+z(x-y)
(x-y)(x+y+z) is the answer
hope this helps
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