Factorise : (x+y) (2a + b) - (3x-2y)(2a+b) options (2x+3y (2a+b)
(3y-2x)(2a+b)
(2x-3y)(2a-b)
(2x-3y)(2a+b)
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Answer:
Step-by-step explanation:
Hello...
Here is your answer:
(x + y) (2a + b) - (3x - 2y) (2a + b)
=> { ( x + y) - (3x - 2y) } (2a + b)
[ Taking (2a + b) common]
=> (x + y - 3x + 2y) ( 2a + b)
=> ( -2x + 3y ) ( 2a + b)
Hope it helped ☺☺☺☺
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