Question

factorise(x+y-2z)^3+(y+z-2x)^3+(z+x-2y)^3​

Answer 1

Answer: -6(x^3+y^3+z^3)

Answer 2

Answer:

a^{3} + b^{3} + c^{3}  = 3 (x+y-2z) (y+z-2x) (z+x-2y)

Step-by-step explanation:

$if \\a+b+c=0 , then \\a^{3} + b^{3} + c^{3} = 3abc$

In this equation,

a = x+y-2z

b = y+z-2x

c = z+x-2y

So,

a + b + c = x + y - 2z + y + z - 2x + z + x - 2y

              = 0

Therefore,

$a^{3} + b^{3} + c^{3} = 3 (x+y-2z) (y+z-2x) (z+x-2y)$

Hope this helped you