Math, asked by chirag0796, 8 months ago

factorise: (x-y/3)^2-49y^2/9​

Answers

Answered by ashwindarshan2007
1

Answer:

\frac{9x^{2} - 6xy + y^{2} - 441y(\frac{2}{9})   }{9}

Step-by-step explanation:

We need to factor out 1/9 from (x-y/3)^2-49y^2/9

So we get the answer as \frac{9x^{2} - 6xy + y^{2} - 441y(\frac{2}{9})   }{9}

Hope it helps

Answered by srikanthn711
20

Answer:

(x+6y/3) (x-8y/3)

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