Question

factorise: (x-y/3)^2-49y^2/9​

Answer 1

Answer:

$\frac{9x^{2} - 6xy + y^{2} - 441y(\frac{2}{9}) }{9}$

Step-by-step explanation:

We need to factor out 1/9 from (x-y/3)^2-49y^2/9

So we get the answer as $\frac{9x^{2} - 6xy + y^{2} - 441y(\frac{2}{9}) }{9}$

Hope it helps

Answer 2

Answer:

(x+6y/3) (x-8y/3)