Question

factorise (x+y)³-27
Answer this question​

Answer 1

Answer:

(x+y-3) (x²+2xy+y²+3(x+y)+9)

Step-by-step explanation:

(x+y)³ - 3³

(x+y)³ - 3³[a³-b³ = (a-b) (a²+ab+b²]

(x+y)³ - 3³[a³-b³ = (a-b) (a²+ab+b²]here a= (x+y) and b = 3

(x+y)³ - 3³[a³-b³ = (a-b) (a²+ab+b²]here a= (x+y) and b = 3(x+y)³ - 3³ = [(x+y) -3] [(x+y)² + 3(x+y) +3²]

[ (a+b)²= a²+2ab+b²]

where a = x and b=y

=[x+y-3] [ (x²+2xy+y²) +3(x+y)+9]

=[x+y-3] [ (x²+2xy+y²) +3(x+y)+9] =(x+y-3) (x²+2xy+y²+3(x+y)+9)