factorise (x-y)³+(y-z)³+(z-x)³
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Answer:
a^3+b^3+c^3=3abc. If a+b+c=0
x-y+y-z+z-x=0
Therefore (x-y) ³ + (y-z) ³ + (z-x) ³=3(x-y)(y-z)(z-x)
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