factorise = (x+y)(3x-7)-(x+y)(2x-11)
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Answer:
Given (x + y)(3x – 7) – (x + y)(2x – 11) (x + y)[(3x – 7) – (2x – 11)] (x + y)[3x – 7 – 2x + 11] (x + y)(x + 4)
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Step-by-step explanation:
(x+y)(3x-7)-(x+y)(2x-11)
3x²-7x + 3xy -7y - ( 2x² - 11x + 2xy -11y )
3x² -7x + 3xy -7y -2x²+ 11x - 2xy + 11y
x² + xy + 4x + 4y
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