Question

factorise: (x+y+z)² - (x-y-z)² + 4y² - 4z²

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Answer 1

Answer:

Given equations are x² + y² + z² = 525

xy + yz + zx = 50

Per algebraic identity.

(x + y + z )² = x² + y² + z² + 2xy + 2yz + 2zx

(x + y + z )² = x² + y² + z² + 2(xy+yz+zx)

= 525+2(50)

= 625

x+y+z = √625

= ±25

After squareroot will be cancelled , the number become ±25.

( x + y + z )² = x² + y² + z² + 2xy +2yz +2zx

( ±25 )² = 525 + 2( 50 )

625 = 525 + 100

625 = 625

L.H.S = R.H.S.

So , the answer is ' ±25 any problems please ask me anything regarding this ❓

Answer 2

Answer:

PLS make my answer brilliant PLS

Step-by-step explanation:

(x + 4)(x + 10)

= x² + (4 + 10)x + 4 x 10 [(x + a)(x + b) = x² + (a + b)x + ab]

= x² + 14x + 40