Question

Factorise : x¹²-y¹².​

Answer 1

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Answer 2

Question:-

To factorise $\tt{{x}^{12}-{y}^{12}}$.

Answer:

• Given, the question is in form of $\tt{{a}^{2}-{b}^{2}}$.
• Hence, as we know, $\tt{{a}^{2}-{b}^{2}=(a+b)(a-b)}$
• Hence, it will be the factoried form.

Real Answer:-

$\tt{{x}^{12}-{y}^{12}}$

(Question in form of the identity)

$\tt{={({x}^{6})}^{2}-{({y}^{6})}^{2}}$

(Hence, we have now written the exponent in form of 6 × 2.

x^6 is a &

y^6 is b)

$\tt{=({x}^{6}+{y}^{6})({x}^{6}-{y}^{6})}$

(Hence, now it is written in the factoriesed form. If we multiply it again, the question will be the answer)

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REQUIRED ANSWER:-

Therefore, the factorised form of $\tt\large{{x}^{12}-{y}^{12}}$ is $\boxed{\large\tt\green{=({x}^{6}+{y}^{6})({x}^{6}-{y}^{6})}}$

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Some More:-

• We can also factorise any expression by the method of $\tt{{x}^{2}+qx+r}$.
• This means qx is the splitted form a number p.
• After splitting, it will be easier to factories.