Question

factorise : (x15-64y3) using identities​

Answer 1

Answer:

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Answer 2

${x}^{15} - 64 {y}^{3} \\ \\ = > {( {(x)}^{5} )}^{3} - {(4y)}^{3} \\ \\ = > ({x}^{5} - 4y)( {x}^{10} + 4 {x}^{5} y + 16{y}^{2} )$

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