Question

factorise x² +10x +7

Answer 1

Answer:

xsq.+9x+x+7

x(x+9)+1(x+7)

(x+9)(x+1)(x+7)

Answer 2

X² + 10x + 7

A=1 ,B=10 and C=7

Now, =b² - 4ac
=(10)² - 4(1)(7)
=100 - 28
=72

0<72
So it has real and distinct roots.

x= (-b ± √b² - 4ac)/(2a)
x= (-10 ± √72)/(2*1)
x= (-10 + √72)/(2) and x= (-10 - √72)/(2)
x= (-10+6√2)/(2) and x= (-10-6√2)/(2)
x= (-5+3√2) and x= (-5-3√2)

Hence zeros/roots are x= (-5+3√2) and x= (-5-3√2)


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