Question

factorise x² + 12x + 32​

Answer 1

Step-by-step explanation:

x^2 + 12 x + 32=0

x^2 +8x+4x+32=0

x (x+8)+4 (x+8)=0

(x+8) (x+4)=0

x+8=0

x= -8

x+4=0

x= -4

Answer 2

Answer:

$x^{2} + 12x+32=0\\Sum=12\\Product=32\\x^{2} +8x+4x=32=0\\(x^{2} + 8x) (4x+32)=0\\x(x+8) +4(x+8)=0\\(x+8)(x+4)=0\\ x+8=0\\x+4=0\\x= -8, -4$

Step-by-step explanation:

The numbers for step factorization are 4 and 8 because the add up to 12, which the coefficient of x and their product is 32 which the product of the coefficient of x^2 and 32.

Then we take the x^2 and 8x in one bracket and 4x and 32 in other bracket

Then from each bracket we choose the common term.

In the bracket x^2 and 8x, we take +x because it is common.

In the bracket 4x+32, we take +4 because it is common

So, we take the common ones together, and form another bracket,

(x+4) and the take the other two brackets as one, like, (x+8).

Then equate the two brackets to zero...

Then to get the equation has zero, in both cases, X has to have the following values

x= -8, -4.

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