Question

factorise x²+13x²+32x+20​

Answer 1

Answer:

$\huge\frak\blue{Answer}$

x³+13x²+32x+20

=(x+1)(x²+12x+20) [∵, for x=-1, x³+13x²+32x+20=-1+13-32+20=0]

=(x+1)(x²+10x+2x+20)

=(x+1){x(x+10)+2(x+10)}

=(x+1){(x+10)(x+2)}

=(x+1)(x+2)(x+10)

Answer 2

$\tt{ {x}^{2} + 13 {x}^{2} + 32x + 20}$

$\tt{14 {x}^{2} + 32x + 20 }$

Divide the whole equation by 2

$\frac{14 {x}^{2} + 32x + 20 }{2}$

$\tt{7 {x}^{2} + 16x + 10 }$

solve this equation by any method you will get roots of the equation.