Question

Factorise x2-19x+78​

Answer 1

Answer:

(x-13)(x-6)

Step-by-step explanation:

i hope this helps

Answer 2

Answer:

The factors of x²-19x+78​ are (x-16) and (x-3)

Step-by-step explanation:

Given expression is   x²-19x+78​

Required to factorize x²-19x+78​

Solution:

Here, we have to factorize x²-19x+78​

Let us factorize it by splitting the middle term

For that, we need to find two numbers such that their sum = -19 and their product = 78

The factors of 78 are  (1, 78), (2, 39), (3, 26), and (6, 13).

Out of these factors, we have 6 and 13 are a pair of factors of 78

Also, -6 and -13 are also pair factors of 78 such that

-6+-13 = -19 and (-6)×( -13) = 78

Hence we have,

x²-19x+78​ =  x²-16x-3x+78​

=x(x-16) -3(x-16)

=(x-16)(x-3)

x²-19x+78 = (x-16)(x-3)

∴ The factors of x²-19x+78​ are (x-16) and (x-3)

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