Question

factorise x²+2xy+2y-1
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Answer 1

Step-by-step explanation:

It is actually very simple if you notice that the quadratic polynomial in y is the square of a linear one.

x2−y2−2y−1=x2−(y2+2y+1)

⟹x2−y2−2y−1=x2−(y+1)2

⟹x2−y2−2y−1=[x+(y+1)][x−(y+1)]

⟹x2−y2−2y−1=(x+y+1)(x−y−1)

Ans : (x-y-1)(x+y+1)

By using a2−b2=(a−b)(a+b)

The only thing which is different from this is you must have to arrange it into this form. So below are the steps.

x2−(y2+2y+1) ==>we take - common

x2−(y+1)2==>(a2+2ab+b2)=(a+b)2

(x−(y+1))(x+(y+1)) =>applying the main rule a2−b2=(a−b)(a+b)

(x−y−1)(x+y+1) =>simplyfying the answer

Answer 2

Step-by-step explanation:

Wrong answer

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