Question

factorise x²+2xy+y²-a²+2ab-b²?​

Answer 1

Answer:

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Answer 2

Answer:

HEY

Step-by-step explanation:

Given- x^2+2xy+y^2-a^2+2ab-b^2

so,By taking - x^2+2xy+y^2-a^2+2ab-b^2

we can write as =

(x^2+2xy+y^2) -(a^2+2ab-b^2)

So we get,,

= (x+y)^2−(a−b)^2

ACCORDING TO THE EQUATION : a^2-b^2=(a+b)(a−b)

We get

=[(x+y)+(a−b)][(x+y)−(a−b)]

=x^2+2xy+y^2-a^2+2ab-b^2

=(a+y+a−b)(a+y−a+b)