factorise x²+2xy+y²-a²+2ab-b²?
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gurudevrajak685:
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HEY
Step-by-step explanation:
Given- x^2+2xy+y^2-a^2+2ab-b^2
so,By taking - x^2+2xy+y^2-a^2+2ab-b^2
we can write as =
(x^2+2xy+y^2) -(a^2+2ab-b^2)
So we get,,
= (x+y)^2−(a−b)^2
ACCORDING TO THE EQUATION : a^2-b^2=(a+b)(a−b)
We get
=[(x+y)+(a−b)][(x+y)−(a−b)]
=x^2+2xy+y^2-a^2+2ab-b^2
=(a+y+a−b)(a+y−a+b)
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