Question

Factorise
x² + 3 √2 + 4​

Answer 1

Answer:

x^2+3√2x+4=(x+√2)(x+2√2)

Step-by-step explanation:

Given:

x^2+3\sqrt{2}x+4x2+32x+4

Now the first step will be that we will split the middle term therefore,

=x^2+2\sqrt{2}x+\sqrt{2}x+4x2+22x+2x+4

=x^2 +2\sqrt{2}x+\sqrt{2}x + 2\sqrt{2\times2}x2+22x+2x+22×2 [2\sqrt{2\times2}=2\times2=4][22×2=2×2=4]

=x^2(x+2\sqrt{2})+\sqrt{2}(x+2\sqrt{2})x2(x+22)+2(x+22)

=(x+\sqrt{2})(x+2\sqrt{2} )(x+2)(x+22)

Answer 2

I hope something is missing in you question plz rewrite the question.