Math, asked by Hansol1, 1 year ago

Factorise: X² + 3√3x +6

Answers

Answered by Rituj1
108

 {x}^{2}  +  \sqrt{3} x + 2 \sqrt{3} x  + 6 \\ x(x +  \sqrt{3)}  \:  + 2 \sqrt{3} (x +  \sqrt{3} ) \\ (x +  \sqrt{3} )(x + 2 \sqrt{3} )
here x= -√3
or -2√3
Answered by mysticd
59

Answer:

x²+3√3x+6 = (x+2√3)(x+√3)

Step-by-step explanation:

We have quadratic expression:

+33x+6

Splitting the middle term, we get

= + 23x + 3x + 6

= +23x+3x+23 ×3

= x(x+23)+3(x+23)

= (x+23)(x+3)

Therefore,

+33x+6 = (x+23)(x+3)

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