Factorise x² +31x+150
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Given:
- x² + 31x + 150
Solution:
x² + 31x + 150
We have to Find that two numbers whose products is 150 and Addition and substraction is 31.
so,
we have two numbers i.e.
25 and 6
:: Product of 25 and 6 150
:: Sum of 25 and 6 31
After putting values together;
x² + 31x + 150
x² + (25 + 6)x + 150 = 0
(x² + 25x) + (6x + 150) = 0
x(x + 25) + 6(x + 25) = 0
(x + 25) (x + 6) = 0
Hence,
- The Factorisation of x² + 31x + 150 is (x + 25) and (x + 6).
- x + 25 = 0 0 - 25 = -25
- x + 6 = 0 0 - 6 = -6
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