Question

factorise :- x²-√3x-6 ​

Answer 1

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factorise :- x²-√3x-6

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It is in the form of a quadratic equation.

Here,we use quadratic formula to find out the roots:-

$= > {x}^{2} - \sqrt{3x} - 6$

Here,a=1;b=-√3 &c=-6

$= > x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a}$

$= > x = \frac{ - ( - \sqrt{3}) ± \sqrt{ {( - \sqrt{3}) }^{2} - 4(1)( - 6)} }{2}$

$= > x = \frac{ \sqrt{3}± \sqrt{3 + 24} }{2}$

$= > x = \frac{ \sqrt{3}± \sqrt{27} } {2}$

$= > x = \frac{ \sqrt{3}±3 \sqrt{3} }{2}$

$\bold{\boxed{ x = \frac{ \sqrt{3}±3 \sqrt{3} }{2}}}$

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