Question

factorise: (x²-3x)(x²-3x+1)-20

Answer 1

I hope it would be helpful to you...

Answer 2

[0010001111]... Hello User... [1001010101]
Here's your answer...

Let x^2-3x = y
Then the polynomial becomes... $y(y + 1) - 20 \\ = {y}^{2} + y - 20 \\ = (y + 5)(y - 4)$
Now we substitute y's value in the polynomial.
$( {x}^{2} - 3x + 5)( {x}^{2} - 3x - 4) \\ = ( {x}^{2} - 3x + 5)(x + 1)(x - 4)$
The first factor cannot be factorised into rational numbers, so I'm leaving it as it is.

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