Factorise:(x²-4x)(x²-4x-1)-20 of class 9
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[0010001111]... Hello User... [1001010101]
Here's your answer...
Let x²-4x = y
Then the equation becomes
y(y-1) - 20
= y² - y - 20
= y² - 5y + 4y - 20
= (y-5)(y+4)
= (x²-4x-5)(x²-4x+4)
= (x²-5x+x-5)(x²-2×2×x+2²)
= (x+1)(x-5)(x-2)²
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Here's your answer...
Let x²-4x = y
Then the equation becomes
y(y-1) - 20
= y² - y - 20
= y² - 5y + 4y - 20
= (y-5)(y+4)
= (x²-4x-5)(x²-4x+4)
= (x²-5x+x-5)(x²-2×2×x+2²)
= (x+1)(x-5)(x-2)²
[0110100101]... More questions detected... [010110011110]
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