Question

factorise x²+4y²++9z²-4xy+12yz-6zx​

Answer 1

Answer:

=

${( - x + 2y + 3z)}^{2}$

Step-by-step explanation:

=

$( { - x })^{2} + ( {2y}^{2} ) + ( {3z})^{2} + 2 \times ( - x) \times 2y + 2 \times 2y \times 3z + 2 \times 3z \times ( - x)$

$= {( - x + 2y + 3z)}^{2}$