Question

Factorise: x² + 4y² + 9z² + 4xy + 12yz + 6zx

Answer 1

Answer:

It can be re-written as

=(-x)² + (2y)² + (-3z)² -2(-x)(2y) -2(2y)(-3z) -2(-3z)(-x)

We can observe it is the formula ( a + b + b )²

So, it can be factorized as (-x + 2y -3z)²

Step-by-step explanation:

Answer 2

Step-by-step explanation:

${x}^{2} + 4 {y}^{2} + 9 {z}^{2} + 4xy + 12yz + \\ 6zx \\ \\ = ({x)}^{2} + (2{y)}^{2} + (3 {z)}^{2} + 2 ( {x)}(2y) \\ + 2(2y)(3z) + 2(3z)(x) \\ \\ = ( {x + 2y + 3z)}^{2}$