Math, asked by spandan339roy, 8 months ago

Factorise x2-5x-24 please answer

Answers

Answered by tanejakca
0
X^2-8x+3x-24
X(x-8)+3(x-8)
(X-8)(x+3)
Answered by TheValkyrie
2

Answer:

\bigstar{\bold{The\:zeros\:are\:8\:and-3}}

Step-by-step explanation:

\Large{\underline{\underline{\bf{Given:}}}}

  • p(x) = x² - 5x - 24

\Large{\underline{\underline{\bf{To\:Find:}}}}

  • The zeros of the polynomial

\Large{\underline{\underline{\bf{Solution:}}}}

→ x² - 5x - 24 =0

→ By splitting the middle term method,

  x² -8x + 3x -24 =0

→ Taking the common factors out,

   x(x - 8) + 3(x - 8) = 0

   (x - 8) (x + 3) = 0

→ Either x - 8=0

            x = 8

→ Or x + 3 = 0

       x = -3

\boxed{\bold{Zeros\:are\:8\:and\:-3}}

\Large{\underline{\underline{\bf{Notes:}}}}

The zeros of a polynomial can be found out by

  • Factorization method
  • Splitting the middle term
  • Completing the square method

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