Question

Factorise x2-(6-2)x-2b​

Answer 1

Answer:

2

−

1

(

6

−

2

)

⋅

−

2

x^{2}-1(6-2) \cdot x-2b

x2−1(6−2)⋅x−2b

Simplify

1

Subtract the numbers

2

−

1

(

6

−

2

)

⋅

−

2

x^{2}-1({\color{#c92786}{6-2}}) \cdot x-2b

x2−1(6−2)⋅x−2b

2

−

1

(

4

)

⋅

−

2

x^{2}-1({\color{#c92786}{4}}) \cdot x-2b

x2−1(4)⋅x−2b

2

Multiply the numbers

2

−

1

⋅

4

−

2

x^{2}{\color{#c92786}{-1}} \cdot {\color{#c92786}{4}}x-2b

x2−1⋅4x−2b

2

−

4

−

2

x^{2}{\color{#c92786}{-4}}x-2b

x2−4x−2b

3

Rearrange terms

2

−

4

−

2

{\color{#c92786}{x^{2}-4x-2b}}

x2−4x−2b

2

−

2

−

4

{\color{#c92786}{x^{2}-2b-4x}}

x2−2b−4x

Solution

2

−

2

−

4

hope it help you