Math, asked by krishnabarnwal843, 14 hours ago

Factorise x² + 6x - 16
Math ch 12
Ex 12.2

Answers

Answered by samirjana797
2

Step-by-step explanation:

x {}^{2}  + 6x - 16 \\  = x {}^{2}  + 8x - 2x - 16 \\  = x(x + 8) - 2(x + 8) \\  = (x + 8)(x - 2)

Answered by tennetiraj86
1

Step-by-step explanation:

Given :-

x² + 6x - 16

To find :-

Factorise x² + 6x - 16 ?

Solution :-

Given expression is x² + 6x - 16

It can be written as

=> x²-2x+8x-16

=> x(x-2)+8(x-2)

=> (x-2)(x+8)

Answer:-

The factorization of x²+6x-16 is (x-2)(x+8)

Check:-

(x-2)(x+8)

=> x(x+8)-2(x+8)

=> x²+8x-2x-16

=> x²+6x-16

Verified the given relations in the given problem.

Used Method:-

→ Splitting the middle term

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