Question

Factorise x² + 6x + 8.​

Answer 1

given that :-

$x ^{2} + 6x + 8$

$= x ^{2} + 4x +2 x + 8(split \: middle \: term)$

$(x ^{2} + 4x) + (2x + 8) \: \: \: \: (group \: pair \: of \: terms)$

$x(x + 4) + 2(x + 4) \: \: (factor \: each \: binomial)$

$= (x + 4) (x + 2) \: \: (factor \: out \: common \: factor)$

$hence \: factors \: of \: x ^{2} + 6x + 8 \: are \: \\ (x + 4)(x + 2)$

$\huge \mathtt \green{hope \: it \: helps \: you}$

Answer 2

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