Question

factorise x2-[a+4]x+4a
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Answer 1

Step-by-step explanation:

${x}^{2} - (a + 4)x + 4a = 0 \\ \\ {x}^{2} - (ax + 4x) + 4a = 0 \\ \\ {x}^{2} - ax - 4x + 4a = 0 \\ \\ x(x - a) - 4(x - a) = 0 \\ \\ (x - 4)(x - a) = 0$

hope it helps......✌✌

Answer 2

Answer:

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