Question

factorise x2-ax-6a2+5ab-b2​

Answer 1

Step-by-step explanation:

Given Factorise  x2-ax-6a2+5ab-b2

Given x^2 + ax – (6a^2 – 5ab + b^2)

     = x^2 + ax – (6a^2 – 3ab – 2ab + b^2)

    = x^2 + ax – [3a(2a – b) – b(2a – b)]

    = x^2 + ax – [(3a – b)(2a – b)]

 = x^2 + [3a – b – (2a – b)]x – (3a – b)(2a – b) [writing a as 3a – b – 2a + b]

= x^2 + (3a – b)x – (2a -b)x – (3a – b)(2a – b)

 = x [ x + (3a – b)] – (2a – b)[x + (3a – b)]

 = [x – (2a – b)] [x + (3a – b)]

 = (x – 2a + b)(x + 3a – b)

Reference link will be

https://brainly.in/question/1189624

Answer 2

Answer:

factories *2ax06a2b2