factorise
x²+ n-(p+1)
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Our goal is to factor xn−1 into a product of polynomials xn−1 = p1p2 ···pk so that each pj is either ... (x − 1)(xm−1 + xm−2 + ··· + x2 + x + 1) = x(xm−1 + xm−2 + xm−3 + ··· + x + 1). −1(xm−1 + ... Let p be the smallest prime factor of n, and suppose n ...
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