factorise x2-root3x-6
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Hey Mate ✌
⏩ Here's your answer,
x² - √3x - 6 = 0
==> x² -2√3x + √3x - 6 = 0
==> x(x - 2√3x) + √3x(x - 2√3) = 0
==> (x + √3)(x - 2√3) = 0
==> x = -√3 or x = 2√3
⭐ Hope it helps you ^_^ ⭐
⏩ Here's your answer,
x² - √3x - 6 = 0
==> x² -2√3x + √3x - 6 = 0
==> x(x - 2√3x) + √3x(x - 2√3) = 0
==> (x + √3)(x - 2√3) = 0
==> x = -√3 or x = 2√3
⭐ Hope it helps you ^_^ ⭐
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